document.write( "Question 550377: A man bought a certain number of chairs for Rs 10,000.He kept one for his own use and sold the rest at the rate Rs 50 more than he gave for one chair.Besides getting his own chair for nothing,he made a profit of Rs 450.How many chairs did he buy?pls...help me. \n" ); document.write( "
Algebra.Com's Answer #358680 by fcabanski(1391)\"\" \"About 
You can put this solution on YOUR website!
n = number of chairs purchased
\n" ); document.write( "p = price paid per chair


\n" ); document.write( "np = 10,000 so p=10,000/n
\n" ); document.write( "(n-1)(p+50)=10450


\n" ); document.write( "np+50n-p-50=10450


\n" ); document.write( "10000+50n-(10000/n)-50=10450


\n" ); document.write( "Subtract 10,000 from both sides and add 50 to both sides. Add 50n and 10,000/n by using n as the common denominator.


\n" ); document.write( "(50n^2 - 10000)/n = 500


\n" ); document.write( "50n^2 - 10000 = 500n


\n" ); document.write( "50n^2 - 500n - 10000 =0


\n" ); document.write( "n^2 - 10n - 200 = 0


\n" ); document.write( "(n-20)(n+10)=0


\n" ); document.write( "n=20 and n=-10


\n" ); document.write( "Can't use -10 because there can't be a negative number of chairs. The answer is 20.\r
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