document.write( "Question 550376: 1.) A man is four times as old as his son. In three years,the father will be three times as old as his son. How old is each three years ago? Please show me the complete procedure,thank you. \n" ); document.write( "
Algebra.Com's Answer #358678 by mananth(16946)\"\" \"About 
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son be x years
\n" ); document.write( "father = 4x\r
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\n" ); document.write( "\n" ); document.write( "after 3 years
\n" ); document.write( "son will be x+3
\n" ); document.write( "father will be 4x+3\r
\n" ); document.write( "\n" ); document.write( "4x+3 = 3(x+3)\r
\n" ); document.write( "\n" ); document.write( "4x+3= 3x+9
\n" ); document.write( "4x-3x=9-3
\n" ); document.write( "x=6\r
\n" ); document.write( "\n" ); document.write( "son's ge = 6 now
\n" ); document.write( "father's age = 24 years\r
\n" ); document.write( "\n" ); document.write( "3 years ago
\n" ); document.write( "son = 3years
\n" ); document.write( "father = 21 years\r
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