document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=550347>Question 550347</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Essay: Show all work. A gardener wants to create a triangular garden in the shape of a right triangle with shortest side length x – 8y ft. and the middle length side x + 6y ft. What is an algebraic expression for the area of the garden? Be sure to multiply this out and express in simplest correct mathematical form, including units.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #358641 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=358641\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of right triangle = 1/2* leg1 * leg2\r<BR>\n" );
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document.write( "Area=(x-8y)(x+6y)\r<BR>\n" );
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document.write( "=x^2-8xy+6xy-48y^2\r<BR>\n" );
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document.write( "=x^2-2xy +48y^2 ft^2\r<BR>\n" );
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