document.write( "Question 550338: The perimeter of a rectangle is 14 feet greater than one and a half times the width. What is the length of the rectangle \n" ); document.write( "
Algebra.Com's Answer #358629 by nyc_function(2741)![]() ![]() You can put this solution on YOUR website! Use P = 2L + 2W.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let P = 3W/2 + 14\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3W + 14 = 2L + 2W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve the equation 3W + 14 = 2L + 2W for L. In other words, isolate the letter L on one side of the equation and that is your answer. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Can you take it from here? \n" ); document.write( " \n" ); document.write( " |