document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=550220>Question 550220</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a person travels at the speed of 40km/hr then he reaches 5min late and if the person travels at the speed of 50km/hr then he reaches 3min,find the distance and the time?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #358592 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=358592\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If a person travels at the speed of 40km/hr then he reaches 5min late and if the person travels at the speed of 50km/hr then he reaches 3min,find the distance and the time?<BR>\n" );
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document.write( "d/40 = t + 5/60<BR>\n" );
document.write( "d/50 = t - 3/60<BR>\n" );
document.write( "------------- Subtract<BR>\n" );
document.write( "d/200 = 8/60<BR>\n" );
document.write( "d = 1600/60 km<BR>\n" );
document.write( "d = 80/3 km<BR>\n" );
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document.write( "t = (80/3)/40 - 5/60 = 2/3 - 1/12<BR>\n" );
document.write( "t = 7/12 hr<BR>\n" );
document.write( "t = 35 minutes to be \"on time\"<BR>\n" );
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