document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=53626>Question 53626</A>: <I><SPAN STYLE=\"word-break: break-all;\"> suppose a ball is dropped from a height of 30ft. and that each bounce reaches 3/8 of the previous height. how high will the ball boucnce on the second bounce? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #35857 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=35857\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> suppose a ball is dropped from a height of 30ft. and that each bounce reaches 3/8 of the previous height. how high will the ball boucnce on the second bounce?<BR>\n" );
document.write( "FIRST BOUNCE HT.REACHED = 30*3/8<BR>\n" );
document.write( "ON SECOND BOUNCE IT WILL REACH = 30*(3/8)(3/8)=270/64 =135/32 FT. </SPAN>\n" );
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