document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=550267>Question 550267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If area and perimeter of a rectangle are given:How can i find out the dimensions?<BR>\n" );
document.write( "Kindly tell me a method to solve such type of problem. K. Sharrma </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #358564 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=358564\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Do it like this:<BR>\n" );
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document.write( "Area of a rectangular field is 120 sq.m and perimeter is 46 m. Findout the dimensions of the field.<BR>\n" );
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document.write( "L*W = 120<BR>\n" );
document.write( "L + W = 23 --> W = 23 - L<BR>\n" );
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document.write( "L*(23 - L) = 120<BR>\n" );
document.write( "23L -L^2 = 120<BR>\n" );
document.write( "L^2 - 23L + 120 = 0<BR>\n" );
document.write( "(L - 8)*(L - 15) = 0<BR>\n" );
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document.write( "--> 8 by 15 <BR>\n" );
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document.write( "If it's not factorable, use the quadratic equation.<BR>\n" );
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