document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=550237>Question 550237</A>: <I><SPAN STYLE=\"word-break: break-all;\"> tow numbers are in the ratio 8:3. If the sum of numbers is 143,find the numbers.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #358544 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=358544\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Two numbers are in the ratio 8:3. If the sum of numbers is 143,find the numbers.\r<BR>\n" );
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document.write( "8:3 is the same as 8x:3x<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "8x + 3x = 143<BR>\n" );
document.write( "11x = 143<BR>\n" );
document.write( "x = 13<BR>\n" );
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document.write( "3x = 39<BR>\n" );
document.write( "8x = 104<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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