document.write( "Question 550146: The internal and external diameters of a hollow hemisherical vessel are 14cm and 21cm respectively.The cost of silver plating of 1cm^2 of its surface is Rs 1.60.Find the total cost of siver plating the vessel all over.\r
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Algebra.Com's Answer #358536 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Surface Area of hemisphere = 2pir^2\r
\n" ); document.write( "\n" ); document.write( "Outside sphere radius = 10.5 (21/2)\r
\n" ); document.write( "\n" ); document.write( "Outside surface area = 2*pi*10.5^2
\n" ); document.write( "692.72 cm^2
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\n" ); document.write( "\n" ); document.write( "Inner radius = 7 (14/2)\r
\n" ); document.write( "\n" ); document.write( "Inner surface area = 2 * pi^7^2
\n" ); document.write( "=307.87 cm^2\r
\n" ); document.write( "\n" ); document.write( "Total surface area =1000.59 cm^2 \r
\n" ); document.write( "\n" ); document.write( "You have to add the rim area
\n" ); document.write( "internal radius = 7 cm
\n" ); document.write( "outer radius = 10.5
\n" ); document.write( "Area of rim = pi* (10.5^2-7^2)
\n" ); document.write( "=192.42 cm^2\r
\n" ); document.write( "\n" ); document.write( "Total = 692.72+307.87 192.42
\n" ); document.write( "=1193.01 cm^2\r
\n" ); document.write( "\n" ); document.write( "1193.01* 1.6=Rs.1908.81\r
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\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca\r
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