document.write( "Question 550154: The volume of a car, V, is directly proportional to the square of its length, l. Calculate the percentage increase in V when l is doubled. \n" ); document.write( "
Algebra.Com's Answer #358489 by TutorDelphia(193)\"\" \"About 
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direct proportion's formula is y=kx. In this case y=V and x=length squared
\n" ); document.write( "\"V=k%2Al%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Let's say the length was 10 and k was 1
\n" ); document.write( "\"V=1%2A%28l0%29%5E2\"
\n" ); document.write( "\"v=1%2A100\"
\n" ); document.write( "vs
\n" ); document.write( "\"v=1%2A%2820%29%5E2\"
\n" ); document.write( "v=1*400\r
\n" ); document.write( "\n" ); document.write( "400 is a 300% increase using the formula new minus old over old or (400-100)/100=3=300%\r
\n" ); document.write( "\n" ); document.write( "Now let's do the general case. Percent increase is new minus old over old\r
\n" ); document.write( "\n" ); document.write( "\"V=k%2Al%5E2\"\r
\n" ); document.write( "\n" ); document.write( "vs
\n" ); document.write( "\"V=k%2A%282l%29%5E2\"
\n" ); document.write( "\"V=k%2A4%28l%5E2%29\"
\n" ); document.write( "new minus old over old:
\n" ); document.write( "\"%28k%2A4%28l%5E2%29-k%2A%28l%5E2%29%29%2F%28k%2A%28l%5E2%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"k%2A3%28l%5E2%29%2F%28k%2A%28l%5E2%29%29\"
\n" ); document.write( "The k and l^2 cancel out and we are left with 3 which is equal to 300%
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