document.write( "Question 549966: How many numbers divisible by 5 and lying between 5000 and 9000 can be formed from the digits 5, 6, 7, 8 and 9? \n" ); document.write( "

Algebra.Com's Answer #358364 by TutorDelphia(193) $\"\"$ $\"About$

You can put this solution on YOUR website!
A number is divisible by 5 if it ends in 5 or 0. Since zero is not an option, it must end in 5.\r
\n" ); document.write( "\n" ); document.write( "Also, we need to note that using the digits given, if we start with a 9, we will go over 9000 (because, again, 0 is not an option)\r
\n" ); document.write( "\n" ); document.write( "Now, assuming we can use each digit more than once,\r
\n" ); document.write( "\n" ); document.write( "for the first digit we have 4 options, for the next, 5 options, 5 options again (and the last digit just had one option)\r
\n" ); document.write( "\n" ); document.write( "So we get that there are 100 possibilities. \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );