document.write( "Question 550033: an integer from 100 through 999 inclusive, is to be chosen at random. What is the probability that the number chosen will have 0 as at least 1 digit? my act answer key got d but i don't know how so i could please explain it to me with work, then that would be great. Help is much appreciated, have a great day!\r
\n" ); document.write( "\n" ); document.write( "a.19/900
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\n" ); document.write( "d.171/900
\n" ); document.write( "e.271/1000
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Algebra.Com's Answer #358359 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
From 100 to 199, the following numbers have one zero in them\r
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\n" ); document.write( "\n" ); document.write( "101, 102, 103, 104, 105, 106, 107, 108, 109, 110, 120, 130, 140, 150, 160, 170, 180, 190, \r
\n" ); document.write( "\n" ); document.write( "There are 18 numbers listed above\r
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\n" ); document.write( "\n" ); document.write( "And there are 9 copies of this similar pattern (just change the first digit; eg: 201, 202, ... is another set, 301, 302, ... is another and so on...)\r
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\n" ); document.write( "\n" ); document.write( "So there are a total of 9*18 = 162 numbers from 100 to 999 that have one number in them\r
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\n" ); document.write( "\n" ); document.write( "The following numbers have two zeros in them\r
\n" ); document.write( "\n" ); document.write( "100, 200, 300, 400, 500, 600, 700, 800, 900\r
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\n" ); document.write( "\n" ); document.write( "and there are 9 numbers listed above\r
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\n" ); document.write( "\n" ); document.write( "So there are a total of 162 + 9 = 171 numbers that have at least one zero\r
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\n" ); document.write( "\n" ); document.write( "So the probability is 171/900 since there are 900 numbers from 100 to 999 (because 999-100+1 = 900)\r
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\n" ); document.write( "\n" ); document.write( "So the answer is choice D
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