document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=548862>Question 548862</A>: <I><SPAN STYLE=\"word-break: break-all;\"> coffee grounds inc. has two kinds of coffee. Coffee A cost $9 per kg and coffee B costs $6 per kg.how many kilograms of each should be combined to obtain 150 kilograms of a blend worth $8 per kilogram </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #358336 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=358336\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> coffee grounds inc. has two kinds of coffee. Coffee A cost $9 per kg and coffee B costs $6 per kg.how many kilograms of each should be combined to obtain 150 kilograms of a blend worth $8 per kilogram<BR>\n" );
document.write( "**<BR>\n" );
document.write( "let x=kilograms of $9 coffee<BR>\n" );
document.write( "150-x=kilograms of $6 coffee<BR>\n" );
document.write( "..<BR>\n" );
document.write( "9x+6(150-x)=8*150<BR>\n" );
document.write( "9x+900-6x=1200<BR>\n" );
document.write( "3x=1200-900=300<BR>\n" );
document.write( "x=100<BR>\n" );
document.write( "150-x=50<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "kilograms of $9 coffee=100<BR>\n" );
document.write( "kilograms of $6 coffee=50 </SPAN>\n" );
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