document.write( "Question 549970: A change machine contains nickels, dimes, and quarters. There are 75 coins in he machine, and the value of the coins is $7.25. There are 5 times as many nickels as dimes. Find the number of coins of each type in the machine. \n" ); document.write( "
Algebra.Com's Answer #358329 by nyc_function(2741)\"\" \"About 
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The problem does not say anything about the number of quarters. So, I'll assume that the number of quarters is x = number of dimes.\r
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\n" ); document.write( "\n" ); document.write( "Based on the information given, I came up with the following equation:\r
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\n" ); document.write( "\n" ); document.write( "5x(0.05) + 0.10(x) + 0.25(x) = 7.25\r
\n" ); document.write( "\n" ); document.write( "Simplifying
\n" ); document.write( "5x(0.05) + 0.10x + 0.025x = 7.25\r
\n" ); document.write( "\n" ); document.write( "Reorder the terms for easier multiplication:
\n" ); document.write( "5 * 0.05x + 0.10x + 0.025x = 7.25\r
\n" ); document.write( "\n" ); document.write( "Multiply 5 * 0.05
\n" ); document.write( "0.25x + 0.10x + 0.025x = 7.25\r
\n" ); document.write( "\n" ); document.write( "Combine like terms: 0.25x + 0.10x = 0.35x
\n" ); document.write( "0.35x + 0.025x = 7.25\r
\n" ); document.write( "\n" ); document.write( "Combine like terms: 0.35x + 0.025x = 0.375x
\n" ); document.write( "0.375x = 7.25\r
\n" ); document.write( "\n" ); document.write( "Solving
\n" ); document.write( "0.375x = 7.25\r
\n" ); document.write( "\n" ); document.write( "Solving for variable 'x'.\r
\n" ); document.write( "\n" ); document.write( "Move all terms containing x to the left, all other terms to the right.\r
\n" ); document.write( "\n" ); document.write( "Divide each side by '0.375'.
\n" ); document.write( "x = 19.33333333\r
\n" ); document.write( "\n" ); document.write( "Simplifying
\n" ); document.write( "x = 19.33333333\r
\n" ); document.write( "\n" ); document.write( "If there is missing information, then write back with the correct question.\r
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