document.write( "Question 550018: A pyramid has a square base with an area of 100 square inches. Each of its triangular faces has a height of 10 inches. What is the surface area of the pyramid? \n" ); document.write( "

Algebra.Com's Answer #358321 by jim_thompson5910(35256) $\"\"$ $\"About$

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Since the area of the base is 100 sq in. this means that the side length of the base is $\"s=sqrt%28100%29=10\"$ inches. So the area of each triangular face is $\"A=%2810%2A10%29%2F2+=+100%2F2+=+50\"$ square inches.\r
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\n" ); document.write( "\n" ); document.write( "Surface Area of Pyramid = Area of base + 4*Area of Triangular Face\r
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\n" ); document.write( "\n" ); document.write( "Surface Area of Pyramid = 100 + 4*50 \r
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\n" ); document.write( "\n" ); document.write( "Surface Area of Pyramid = 100 + 200\r
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\n" ); document.write( "\n" ); document.write( "Surface Area of Pyramid = 300 square inches \n" ); document.write( "

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