document.write( "Question 550017: The width of a rectangle is one-fifth the length. The perimeter of the rectangle is 30 feet. What is the width of the rectangle?
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document.write( " how tdo you do this ? \n" );
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Algebra.Com's Answer #358320 by prateekagrawal(56)![]() ![]() ![]() You can put this solution on YOUR website! let length is 5x. \n" ); document.write( "then width= 5x/5 = x \n" ); document.write( ". \n" ); document.write( "so, perimeter=2(length+width) \n" ); document.write( "30=2(5x+x) \n" ); document.write( "30= 2*6x \n" ); document.write( "30=12x \n" ); document.write( "x=30/12 = 2.5 feet \n" ); document.write( "so, length= 5*2.5 = 12.5 feet \n" ); document.write( "and width= 2.5 feet \n" ); document.write( " |