document.write( "Question 550017: The width of a rectangle is one-fifth the length. The perimeter of the rectangle is 30 feet. What is the width of the rectangle?
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Algebra.Com's Answer #358320 by prateekagrawal(56)\"\" \"About 
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let length is 5x.
\n" ); document.write( "then width= 5x/5 = x
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\n" ); document.write( "so, perimeter=2(length+width)
\n" ); document.write( "30=2(5x+x)
\n" ); document.write( "30= 2*6x
\n" ); document.write( "30=12x
\n" ); document.write( "x=30/12 = 2.5 feet
\n" ); document.write( "so, length= 5*2.5 = 12.5 feet
\n" ); document.write( "and width= 2.5 feet
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