document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=549988>Question 549988</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A peice of wire is 42 com long and is bent into the shape of a rectangle who width is twice its length. Find the dimensions of the recanhle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #358313 by </B><A HREF=/tutors/aboutme.mpl?userid=TutorDelphia><B>TutorDelphia(193)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TutorDelphia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=TutorDelphia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=358313\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The 42cm will become the rectangle's perimeter. \r<BR>\n" );
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document.write( "Our relevant formulas is<BR>\n" );
document.write( "P=2L+2W (perimeter equals 2 times the length and 2 times the width)\r<BR>\n" );
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document.write( "We also know<BR>\n" );
document.write( "W=2L<BR>\n" );
document.write( "We can use that to sub in\r<BR>\n" );
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document.write( "P=2L+2(2L)\r<BR>\n" );
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document.write( "P=6L\r<BR>\n" );
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document.write( "42=6L<BR>\n" );
document.write( "L=7\r<BR>\n" );
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document.write( "W=2L<BR>\n" );
document.write( "W=2(7)<BR>\n" );
document.write( "W=14\r<BR>\n" );
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document.write( "And to check 2*14+2*7=42<BR>\n" );
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