document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=547939>Question 547939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log3^(4x-7)=(1/9) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #358283 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=358283\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log3^(4x-7)=(1/9)<BR>\n" );
document.write( "convert to exponential form: base(3) raised to log of number(1/9)=number(4x-7)<BR>\n" );
document.write( "3^(1/9)=4x-7<BR>\n" );
document.write( "1.1298=4x-7<BR>\n" );
document.write( "4x=1.1298+7=8.1298<BR>\n" );
document.write( "x=8.1298/4<BR>\n" );
document.write( "x&#8776;2.03245 </SPAN>\n" );
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