document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=549976>Question 549976</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the volume of a right circular cone increases by 33.1% to form a similar cone, find the percentage increase in its height </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #358268 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=358268\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the volume of a right circular cone increases by 33.1% to form a similar cone, find the percentage increase in its height<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "1 = 33.1% --> 1.331 times the volume<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Vol+=+pi%2Ar%5E2%2Ah%2F3 ALIGN=MIDDLE  ALT=\"Vol+=+pi%2Ar%5E2%2Ah%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "If the 2 are similar, the height and radius are in the same ratio, and volume is a function of the product.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2Ar%29%5E2%2A%28x%2Ah%29+=+x%5E3%2Ar%5E2%2Ah ALIGN=MIDDLE  ALT=\"%28x%2Ar%29%5E2%2A%28x%2Ah%29+=+x%5E3%2Ar%5E2%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x^3 = 1.331<BR>\n" );
document.write( "x = 1.1<BR>\n" );
document.write( "An increase of 10%<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );