document.write( "Question 549939: There are 2 work each of 3 volumes and 2 work each of 2 volumes. In how many ways can the 10 books be placed on a shelf so that the volumes of same work are not separated ?
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document.write( "Answer- 3456 \n" );
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Algebra.Com's Answer #358242 by Theo(13342)![]() ![]() You can put this solution on YOUR website! you have 4 different works. \n" ); document.write( "on a shelf, they can be arranged in 24 ways. \n" ); document.write( "using the permutation formula, this works out to be: \n" ); document.write( "4! = 4*3*2*1 = 24 \n" ); document.write( "each of the 3 volume works can be arranged in 6 ways. \n" ); document.write( "using the permutation formula, this works out to be: \n" ); document.write( "3! = 3*2*1 = 6 \n" ); document.write( "each of the 2 volume works can be arranged in 2 ways. \n" ); document.write( "using the permutation formula, this works out to be: \n" ); document.write( "2! = 2*1 = 2 \n" ); document.write( "for each of the 24 possible arrangements of works, you have 6 * 6 * 2 * 2 possible arrangements within each work. \n" ); document.write( "this comes out to be 24 * 6 * 6 * 2 * 2 = 3456 \n" ); document.write( " \n" ); document.write( " |