document.write( "Question 549949: If x ml pure alcohol is added to 400 ml of a 15% solution and after adding its strength becomes 32%, then the value of x is what? \n" ); document.write( "

Algebra.Com's Answer #358236 by josmiceli(19441) $\"\"$ $\"About$

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Alcohol in 15% solution = $\"+.15%2A400+=+60+\"$ ml
\n" ); document.write( " $\"+%28+x+%2B+60+%29+%2F+%28+x+%2B+400+%29+=+.32+\"$
\n" ); document.write( " $\"+x+%2B+60+=+.32%2A%28+x+%2B+400+%29+\"$
\n" ); document.write( " $\"+x+%2B+60+=+.32x+%2B+128+\"$
\n" ); document.write( " $\"+.68x+=+68+\"$
\n" ); document.write( " $\"+x+=+100+\"$
\n" ); document.write( "x is 100 ml
\n" ); document.write( "check answer:
\n" ); document.write( " $\"+%28+100+%2B+60+%29+%2F+%28+100+%2B+400+%29+=+.32+\"$
\n" ); document.write( " $\"+160+%2F+500+=+.32+\"$
\n" ); document.write( " $\"+8%2F25+=+.32+\"$
\n" ); document.write( " $\"+8+=+8+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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