document.write( "Question 549930: when Marvin was 2 km. upstream from where he started his canoe trip, he passed a log floating with the current. After paddling upstream for one more hour, he paddled back and reached his starting point just as the log arrived.\r
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document.write( "How fast was the current flowing? \n" );
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Algebra.Com's Answer #358199 by stanbon(75887) ![]() You can put this solution on YOUR website! when Marvin was 2 km. upstream from where he started his canoe trip, he passed a log floating with the current. After paddling upstream for one more hour, he paddled back and reached his starting point just as the log arrived. \n" ); document.write( "How fast was the current flowing? \n" ); document.write( "------- \n" ); document.write( "Draw the picture: \n" ); document.write( "Upstream DATA: \n" ); document.write( "time = 1Downstream DATA: \n" ); document.write( "distance = p-c+2 km ; rate = p+c km/h ; time = (p-c+2)/(p+c) hrs \n" ); document.write( "--------- \n" ); document.write( "Log DATA: \n" ); document.write( "rate = c km/h ; distance 2 km ; time = d/r = 2/c hrs \n" ); document.write( "-------------------------------------------------------- \n" ); document.write( "Equation: \n" ); document.write( "time up + time down = 2/c hrs \n" ); document.write( "1 hr + (p-c+2)/(p+c) hr = 2/c hr \n" ); document.write( "----- \n" ); document.write( "Multiplthru by c(p+c) to get: \n" ); document.write( "c(p+c) + c(p-c+2) = 2(p+c) \n" ); document.write( "----- \n" ); document.write( "cp + c^2 + cp-c^2+2c = 2p+2c \n" ); document.write( "---- \n" ); document.write( "2cp = 2p \n" ); document.write( "cp = p \n" ); document.write( "current speed is 1 km/hr \n" ); document.write( "============================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================= \n" ); document.write( " \n" ); document.write( " |