document.write( "Question 549930: when Marvin was 2 km. upstream from where he started his canoe trip, he passed a log floating with the current. After paddling upstream for one more hour, he paddled back and reached his starting point just as the log arrived.\r
\n" ); document.write( "\n" ); document.write( "How fast was the current flowing?
\n" ); document.write( "

Algebra.Com's Answer #358199 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
when Marvin was 2 km. upstream from where he started his canoe trip, he passed a log floating with the current. After paddling upstream for one more hour, he paddled back and reached his starting point just as the log arrived.
\n" ); document.write( "How fast was the current flowing?
\n" ); document.write( "-------
\n" ); document.write( "Draw the picture:
\n" ); document.write( "Upstream DATA:
\n" ); document.write( "time = 1Downstream DATA:
\n" ); document.write( "distance = p-c+2 km ; rate = p+c km/h ; time = (p-c+2)/(p+c) hrs
\n" ); document.write( "---------
\n" ); document.write( "Log DATA:
\n" ); document.write( "rate = c km/h ; distance 2 km ; time = d/r = 2/c hrs
\n" ); document.write( "--------------------------------------------------------
\n" ); document.write( "Equation:
\n" ); document.write( "time up + time down = 2/c hrs
\n" ); document.write( "1 hr + (p-c+2)/(p+c) hr = 2/c hr
\n" ); document.write( "-----
\n" ); document.write( "Multiplthru by c(p+c) to get:
\n" ); document.write( "c(p+c) + c(p-c+2) = 2(p+c)
\n" ); document.write( "-----
\n" ); document.write( "cp + c^2 + cp-c^2+2c = 2p+2c
\n" ); document.write( "----
\n" ); document.write( "2cp = 2p
\n" ); document.write( "cp = p
\n" ); document.write( "current speed is 1 km/hr
\n" ); document.write( "=============================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "=================
\n" ); document.write( "
\n" ); document.write( "
\n" );