document.write( "Question 549909: Solve: absolute value of 8X-2= absolute value of 9X+4. \n" ); document.write( "
Algebra.Com's Answer #358170 by prateekagrawal(56)\"\" \"About 
You can put this solution on YOUR website!
first we need to break this in three parts.
\n" ); document.write( "8x-2= 0 then x= 2/8= 1/4
\n" ); document.write( "9x+4=0 then x= -4/9
\n" ); document.write( "so, three intervals are x<-4/9, -4/9<=x<=1/4 and x>1/4\r
\n" ); document.write( "\n" ); document.write( "for the first interval x<-4/9
\n" ); document.write( "both expressions are negative, so
\n" ); document.write( "-(8x-2)=-(9x+4)
\n" ); document.write( "8x-2 =9x+4
\n" ); document.write( "-6=x, this is less than -4/9so x=-6 is one solution.\r
\n" ); document.write( "\n" ); document.write( "for the second interval -4/9 < =x <=1/4
\n" ); document.write( "first part is negative and second is positive.
\n" ); document.write( "so,
\n" ); document.write( "-(8x-2)=9x+4
\n" ); document.write( "-8x+2 = 9x+4
\n" ); document.write( "17x= -2
\n" ); document.write( "x= -2/17
\n" ); document.write( "so, this is also lies in the interval range.\r
\n" ); document.write( "\n" ); document.write( "now, for the third interval x>1/4 , both are positive
\n" ); document.write( "so,
\n" ); document.write( "8x-2=9x+4
\n" ); document.write( "x=-6
\n" ); document.write( "this is not greater than 1/4
\n" ); document.write( "so, this is no solution for the third case.
\n" ); document.write( "so,\r
\n" ); document.write( "\n" ); document.write( "x= -6 and -2/17 are the answers of this question.
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