document.write( "Question 549909: Solve: absolute value of 8X-2= absolute value of 9X+4. \n" ); document.write( "
Algebra.Com's Answer #358170 by prateekagrawal(56)![]() ![]() ![]() You can put this solution on YOUR website! first we need to break this in three parts. \n" ); document.write( "8x-2= 0 then x= 2/8= 1/4 \n" ); document.write( "9x+4=0 then x= -4/9 \n" ); document.write( "so, three intervals are x<-4/9, -4/9<=x<=1/4 and x>1/4\r \n" ); document.write( "\n" ); document.write( "for the first interval x<-4/9 \n" ); document.write( "both expressions are negative, so \n" ); document.write( "-(8x-2)=-(9x+4) \n" ); document.write( "8x-2 =9x+4 \n" ); document.write( "-6=x, this is less than -4/9so x=-6 is one solution.\r \n" ); document.write( "\n" ); document.write( "for the second interval -4/9 < =x <=1/4 \n" ); document.write( "first part is negative and second is positive. \n" ); document.write( "so, \n" ); document.write( "-(8x-2)=9x+4 \n" ); document.write( "-8x+2 = 9x+4 \n" ); document.write( "17x= -2 \n" ); document.write( "x= -2/17 \n" ); document.write( "so, this is also lies in the interval range.\r \n" ); document.write( "\n" ); document.write( "now, for the third interval x>1/4 , both are positive \n" ); document.write( "so, \n" ); document.write( "8x-2=9x+4 \n" ); document.write( "x=-6 \n" ); document.write( "this is not greater than 1/4 \n" ); document.write( "so, this is no solution for the third case. \n" ); document.write( "so,\r \n" ); document.write( "\n" ); document.write( "x= -6 and -2/17 are the answers of this question. \n" ); document.write( " |