document.write( "Question 549890: 35-12x=-104\r
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Algebra.Com's Answer #358159 by jim_thompson5910(35256)\"\" \"About 
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\"35-12x=-104\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-12x=-104-35\" Subtract \"35\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-12x=-139\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-139%29%2F%28-12%29\" Divide both sides by \"-12\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=139%2F12\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=139%2F12\"
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