document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=549728>Question 549728</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The age of father is twice the age of elder son.Ten years hence,the age of father will be three times the younger son.If the difference in the ages of two sons is 15 years,Then the age of father is? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357995 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let elder son be x<BR>\n" );
document.write( "father = 2x<BR>\n" );
document.write( "y = younger son=(x-15)\r<BR>\n" );
document.write( "\n" );
document.write( "10 years later<BR>\n" );
document.write( "2x+10=3(x-15+10)<BR>\n" );
document.write( "2x+10=3(x-5)<BR>\n" );
document.write( "3x-2x=25\r<BR>\n" );
document.write( "\n" );
document.write( "x=25<BR>\n" );
document.write( "y=10<BR>\n" );
document.write( "father = 50 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );