document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=549722>Question 549722</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x+y=1 2x-y=-2\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357980 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357980\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1	x	+	1	y	=	1	.............1<BR>\n" );
document.write( "2	x		-1	y	=	-2	.............2<BR>\n" );
document.write( "Eliminate 	y						<BR>\n" );
document.write( "Add the two equations							<BR>\n" );
document.write( "3	x				=	-1.00	<BR>\n" );
document.write( "/	3						<BR>\n" );
document.write( "x	=	-  1/ 3					<BR>\n" );
document.write( "plug value of 			x	in (1)			<BR>\n" );
document.write( "1	x	+		y	=	1	<BR>\n" );
document.write( "-0.33		+		y	=	1	<BR>\n" );
document.write( "			y	=	1	+<BR>\n" );
document.write( "				y	=	4/3	<BR>\n" );
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document.write( "m.ananth@hotmail.ca							<BR>\n" );
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