document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=549713>Question 549713</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if ABCD is a square of area of 4 sq cm, find the radius of the circle that passes through all the vertices of the square.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357973 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357973\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> square <BR>\n" );
document.write( "Area = 4cm^2\r<BR>\n" );
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document.write( "side = 2\r<BR>\n" );
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document.write( "Use Pythagoras theorem<BR>\n" );
document.write( "diagonal = hypotenuse \r<BR>\n" );
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document.write( "diagonal ^2= side1^2+side2^2\r<BR>\n" );
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document.write( "diagonal^2=2^2+2^2\r<BR>\n" );
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document.write( "diagonal^2=8\r<BR>\n" );
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document.write( "diagonal = sqrt(8)\r<BR>\n" );
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document.write( "the radius of the sircle will be 1/2 the diagonal<BR>\n" );
document.write( "sqrt(8)/2<BR>\n" );
document.write( "=2sqrt(2)/2<BR>\n" );
document.write( "=sqrt(2)<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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