document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=549712>Question 549712</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve this quadratic equation? It doesn't appear in the standard quadratic form so I'm unsure how to solve the problems I have like this one problem. I do know how to solve the ones that look like f(x) = a x^2 + b x + c ; please help me with this:\r<BR>\n" );
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document.write( "x^3-2x^2+5x-6=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357972 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357972\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use factor theorem.<BR>\n" );
document.write( " f(x) = x^3+2x^2-5x-6<BR>\n" );
document.write( " f(-1) = -1+2+5-6 = 0<BR>\n" );
document.write( " So, x+1 is a factor<BR>\n" );
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document.write( "By synthetic division, <BR>\n" );
document.write( "x^3+2x^2-5x-6 = (x+1)(x^2+x-6) = (x+1)(x-2)(x+3) = 0<BR>\n" );
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document.write( " x = -1, 2, -3\r<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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