document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=549692>Question 549692</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many pounds of nuts selling for $3.00 per pound should be mixed with 3 pounds of nuts selling for $1.20 a pound to obtain a mix selling for $2.46 per pound?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357959 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357959\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 	--------price	----------------	quantity									<BR>\n" );
document.write( "nuts type I	1.2	----------------			3	lb						<BR>\n" );
document.write( "nuts type II	3	----------------			x	lb						<BR>\n" );
document.write( "Mixture	2.46	----------------	3	+	x	lb						<BR>\n" );
document.write( "												<BR>\n" );
document.write( "1.2*3+3x=2.46(3+x)<BR>\n" );
document.write( "3.6+3x=7.38+2.46x				<BR>\n" );
document.write( "3x-2.4x=7.38-3.6				<BR>\n" );
document.write( "0.54	x	=	3.78									<BR>\n" );
document.write( "/	0.54											<BR>\n" );
document.write( "x	=	7										<BR>\n" );
document.write( "		7	lb		of	nuts type II						<BR>\n" );
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