document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=549656>Question 549656</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determine the values &#8203;&#8203;of K for which the following system has a nonzero solution:\r<BR>\n" );
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document.write( "Kx + Ky = 0<BR>\n" );
document.write( "4x + 2Ky = 0\r<BR>\n" );
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document.write( "The official answer is K=0 and K=2\r<BR>\n" );
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document.write( "Help me please! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357937 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357937\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Kx + Ky = 0<BR>\n" );
document.write( "4x + 2Ky = 0 <BR>\n" );
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document.write( "multiply the 1st equation by 2, and you have<BR>\n" );
document.write( "2kx + 2ky = 0<BR>\n" );
document.write( "4x  + 2ky = 0<BR>\n" );
document.write( "-------------------subtraction eliminates 2ky, find k<BR>\n" );
document.write( "2kx - 4x + 0 = 0<BR>\n" );
document.write( "2kx = 4x<BR>\n" );
document.write( "divide both sides by 2x<BR>\n" );
document.write( "k = 2<BR>\n" );
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document.write( "I'm not sure how you would get k=0 </SPAN>\n" );
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