document.write( "Question 549639: the half-life of a particular element is 4 days. after 20 days a sample has been reduced to a mass of 0.375g. what was the initial mass of the sample? \n" ); document.write( "
Algebra.Com's Answer #357926 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! the half-life of a particular element is 4 days. \n" ); document.write( "after 20 days a sample has been reduced to a mass of 0.375g. \n" ); document.write( "what was the initial mass of the sample? \n" ); document.write( ": \n" ); document.write( "the radioactive decay formula: A = Ao*2^(-t/h), where \n" ); document.write( "A = resulting amt after t time \n" ); document.write( "Ao = initial amt \n" ); document.write( "t = time \n" ); document.write( "h = half-life of substance \n" ); document.write( ": \n" ); document.write( "Ao*2^(-20/4) = .375 \n" ); document.write( "Ao*2^(-5) = .375 \n" ); document.write( "Ao*.03125 = .375 \n" ); document.write( "Ao = \n" ); document.write( "Ao = 12 grams, the initial mass of the sample \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this on your calc: enter 12*2^(-20/4) result .375\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |