document.write( "Question 549645: I need help on solving a linear system using elimination.
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document.write( "The question is
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document.write( "a/2 + b/3 = 1
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document.write( "a/4 - 2b/3 = -1\r
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document.write( "Thank you very much! (I may need your help for many things in math as well!:)) \n" );
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Algebra.Com's Answer #357922 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! a/2 + b/3 = 1 \n" ); document.write( "a/4 - 2b/3 = -1 \n" ); document.write( "------------- \n" ); document.write( "Step 1, eliminate fractions. \n" ); document.write( "a/2 + b/3 = 1 times 6 --> 3a + 2b = 6 \n" ); document.write( "a/4 - 2b/3 = -1 time 12 --> 3a - 8b = -12 \n" ); document.write( "------------- \n" ); document.write( "3a + 2b = 6 \n" ); document.write( "3a - 8b = -12 \n" ); document.write( "---------------- Subtract \n" ); document.write( "0a + 10b = 18 \n" ); document.write( "b = 18/10 = 9/5 \n" ); document.write( "------------------ \n" ); document.write( "Sub for b in either eqn (with integers) and find a. \n" ); document.write( " \n" ); document.write( " |