document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=549614>Question 549614</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x(x-5) + (x-5)\r<BR>\n" );
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document.write( "I know the answer is (x-5)(3x+1) and that I need to factor and the gcf is a binomial but for the life of me I can not remember how this is done. Please show a step by step process. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357918 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357918\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> think of it as <BR>\n" );
document.write( "y*z+1*z<BR>\n" );
document.write( "(y+1)*(z)<BR>\n" );
document.write( "where 3x=y and (x-5)=z\r<BR>\n" );
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document.write( " </SPAN>\n" );
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