document.write( "Question 549490: divide $80 among three people so that tha second will have a twice as much as the first, and the therd will have $5 less than the second. \n" ); document.write( "
Algebra.Com's Answer #357908 by fcabanski(1391)\"\" \"About 
You can put this solution on YOUR website!
Call the people A, B and C


\n" ); document.write( "If A has A dollars,
\n" ); document.write( "Then B has 2A dollars (twice as much as the first)
\n" ); document.write( "Then C has 2A-5 dollars (5 less than B, and B has 2A)


\n" ); document.write( "Their sum is 80 so:


\n" ); document.write( "A+2A+2A-5=80
\n" ); document.write( "5A-5=80
\n" ); document.write( "5A=85
\n" ); document.write( "A=17

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\n" ); document.write( "\n" ); document.write( "A has $17, B has 2A=2*17=$34, C has 2A-5 = $34-5 = $29
\n" ); document.write( "

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