document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=549573>Question 549573</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if i traveled around the equator at 60 mph and 200 miles above the equator.  How long would it take?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357874 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357874\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if i traveled around the equator at 60 mph and 200 miles above the equator.  How long would it take?<BR>\n" );
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document.write( "r = radius of the Earth in miles<BR>\n" );
document.write( "C = 2*pi*(r+200)<BR>\n" );
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document.write( "d = r*t<BR>\n" );
document.write( "t = d/r = 2*pi*(r+200)/60 hours<BR>\n" );
document.write( "= (pi*r + 200pi)/30 hours<BR>\n" );
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