document.write( "Question 549585: Marie is 4 years younger than Julie. In 3 years the product of their ages will be 410. How old are they?\r
\n" ); document.write( "\n" ); document.write( "Marie= x-4
\n" ); document.write( "Julie= x\r
\n" ); document.write( "\n" ); document.write( "julie= (x+3)
\n" ); document.write( "marie= x-4+3 = (x-1)\r
\n" ); document.write( "\n" ); document.write( "(x+3)(x-1)= 410\r
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Algebra.Com's Answer #357872 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Marie is 4 years younger than Julie. In 3 years the product of their ages will be 410. How old are they?
\n" ); document.write( "Marie= x-4
\n" ); document.write( "Julie= x
\n" ); document.write( "julie= (x+3)
\n" ); document.write( "marie= x-4+3 = (x-1)
\n" ); document.write( "(x+3)(x-1)= 410
\n" ); document.write( "----
\n" ); document.write( "x^2+2x-413 = 0
\n" ); document.write( "---
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = [-2 + sqrt(4-4*-413)]/2
\n" ); document.write( "-----
\n" ); document.write( "x = [-2 + 40.69]/2
\n" ); document.write( "-----
\n" ); document.write( "x = 19.35 years (Julie's age now)
\n" ); document.write( "x-4 = 15.35 years (Marie's age now)
\n" ); document.write( "----
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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