document.write( "Question 549564: lilly and wilma working together can complete a job in 1 and 1/3 hours. if it takes lilly working alone 2 hours less than wilma to do the job, find the time inquired by each woman working alone. \n" ); document.write( "
Algebra.Com's Answer #357855 by nerdybill(7384)\"\" \"About 
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lilly and wilma working together can complete a job in 1 and 1/3 hours. if it takes lilly working alone 2 hours less than wilma to do the job, find the time inquired by each woman working alone.
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\n" ); document.write( "1 and 1/3 hours = 1 + 1/3 = 3/3 + 1/3 = 4/3 hours
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\n" ); document.write( "Let x = time (hours) it takes Wilma to do the job
\n" ); document.write( "then
\n" ); document.write( "x-2 = time (hours) it takes Lilly to do the job
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\n" ); document.write( "(4/3)(1/x + 1/(x-2)) = 1
\n" ); document.write( "multiplying both sides by 3:
\n" ); document.write( "4(1/x + 1/(x-2)) = 3
\n" ); document.write( "multiplying both sides by x(x-2):
\n" ); document.write( "4((x-2) + x) = 3x(x-2)
\n" ); document.write( "4(2x-2) = 3x^2-6x
\n" ); document.write( "8x-8 = 3x^2-6x
\n" ); document.write( "-8 = 3x^2-14x
\n" ); document.write( "0 = 3x^2-14x+8
\n" ); document.write( "0 = 3x^2-12x-2x+8
\n" ); document.write( "0 = (3x^2-12x)-(2x-8)
\n" ); document.write( "0 = 3x(x-4)-2(x-4)
\n" ); document.write( "0 = (x-4)(3x-2)
\n" ); document.write( "x = {2/3, 4}
\n" ); document.write( "We can toss out the 2/3 (extraneous) because it doesn't make sense leaving
\n" ); document.write( "x = 4 hours (Wilma)
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\n" ); document.write( "Lilly:
\n" ); document.write( "x-2 = 4-2 = 2 hours
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