document.write( "Question 549512: Find the sum of all numbers greater than 10000 formed by using the digits 1,3,5,7,9, no digits being repeated in any number.
\n" ); document.write( "Answer- 6666600
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Algebra.Com's Answer #357829 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
Here's why:\r
\n" ); document.write( "\n" ); document.write( "Suppose you had this long list of them to add: \r
\n" ); document.write( "\n" ); document.write( " 13579
\n" ); document.write( " 13597
\n" ); document.write( " 13759
\n" ); document.write( " .....
\n" ); document.write( " .....
\n" ); document.write( " 97351
\n" ); document.write( " 97513
\n" ); document.write( " 97531
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\n" ); document.write( "\n" ); document.write( "There would be 5! or 120 numbers to add. Each vertical column of digits
\n" ); document.write( "contains an equal number of 1's, 3's, 5's, 7's and 9's. So since 120÷5
\n" ); document.write( "is 24, the sum of each column is 24×(1+3+5+7+9) = 600, The first column
\n" ); document.write( "represents 10000's, the 2nd column represents 1000's, etc. Therefore the
\n" ); document.write( "sum is:\r
\n" ); document.write( "\n" ); document.write( "600×10000 + 600×1000 + 600×100 + 600×10 + 600 =\r
\n" ); document.write( "\n" ); document.write( "600×(10000 + 1000 + 100 + 10 + 1) =\r
\n" ); document.write( "\n" ); document.write( "600×(11111) = 6666600 \r
\n" ); document.write( "\n" ); document.write( "Edwin
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