document.write( "Question 549394: A chemist has 40 ounces of a solution of iodine and alcohol, which is 15% iodine. How much pure iodine must be added to make a solution that is 20% iodine? \n" ); document.write( "
Algebra.Com's Answer #357798 by mananth(16946)![]() ![]() You can put this solution on YOUR website! --------percent ---------------- quantity \n" ); document.write( "Iodine 15 ---------------- 40 oz \n" ); document.write( "Iodine 100 ---------------- x oz \n" ); document.write( "Mixture 20 ---------------- 40 + x oz \n" ); document.write( " \n" ); document.write( "15*40+100x=20(40+x) \n" ); document.write( "600+100x=800+20x \n" ); document.write( "100x-20x=800-600 \n" ); document.write( "80x=200 \n" ); document.write( "/ 80 \n" ); document.write( "x = 2.5 \n" ); document.write( "2.5 oz of Iodine \n" ); document.write( " \n" ); document.write( " |