document.write( "Question 549394: A chemist has 40 ounces of a solution of iodine and alcohol, which is 15% iodine. How much pure iodine must be added to make a solution that is 20% iodine? \n" ); document.write( "
Algebra.Com's Answer #357798 by mananth(16946)\"\" \"About 
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--------percent ---------------- quantity
\n" ); document.write( "Iodine 15 ---------------- 40 oz
\n" ); document.write( "Iodine 100 ---------------- x oz
\n" ); document.write( "Mixture 20 ---------------- 40 + x oz
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\n" ); document.write( "15*40+100x=20(40+x)
\n" ); document.write( "600+100x=800+20x
\n" ); document.write( "100x-20x=800-600
\n" ); document.write( "80x=200
\n" ); document.write( "/ 80
\n" ); document.write( "x = 2.5
\n" ); document.write( "2.5 oz of Iodine
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