document.write( "Question 549472: i would like work shown please,using the substitution method\r
\n" ); document.write( "\n" ); document.write( "x=-3-y
\n" ); document.write( "5x-3y=1
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Algebra.Com's Answer #357780 by TutorDelphia(193)\"\" \"About 
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x=-3-y
\n" ); document.write( "5x-3y=1\r
\n" ); document.write( "\n" ); document.write( "We already have this solved for x, so lets plug in for x\r
\n" ); document.write( "\n" ); document.write( "5(-3-y)-3y=1
\n" ); document.write( "distribute the 5\r
\n" ); document.write( "\n" ); document.write( "-15-5y-3y=1
\n" ); document.write( "combine like terms\r
\n" ); document.write( "\n" ); document.write( "-15-8y=1
\n" ); document.write( "add 15 to both sides\r
\n" ); document.write( "\n" ); document.write( "-8y=16
\n" ); document.write( "divide both sides by -8
\n" ); document.write( "y=-2\r
\n" ); document.write( "\n" ); document.write( "And plug in two for y
\n" ); document.write( "x=-3-(-2)=-3+2
\n" ); document.write( "x=-1
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