document.write( "Question 549121: A SQUARE AND A RECTANGLE HAVE THE SAME AREA. THE LENGTH OF THE RECTANGLE IS 8 MORE THAN A SIDE OF THE SQUARE, AND THE WIDTH OF THE RECTANGLEIS 4 LESS THAN A SIDE OF THE SQUARE. FIND A SIDE OF THE SQUARE.\r
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Algebra.Com's Answer #357766 by ankor@dixie-net.com(22740)\"\" \"About 
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A SQUARE AND A RECTANGLE HAVE THE SAME AREA.
\n" ); document.write( "THE LENGTH OF THE RECTANGLE IS 8 MORE THAN A SIDE OF THE SQUARE, AND THE WIDTH OF THE RECTANGLEIS 4 LESS THAN A SIDE OF THE SQUARE.
\n" ); document.write( " FIND A SIDE OF THE SQUARE.
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\n" ); document.write( "Let x = the side of the square
\n" ); document.write( "then
\n" ); document.write( "x^2 = the area of the square
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\n" ); document.write( "(x+8) = the length of the rectangle
\n" ); document.write( "(x-4) = the width of the rectangle
\n" ); document.write( "then FOIL
\n" ); document.write( "(x+8)(x-4) = x^2 - 4x + 8x - 32
\n" ); document.write( "x^2 + 4x - 32 = the area of the rectangle
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\n" ); document.write( "Given the areas areas are equal
\n" ); document.write( "x^2 + 4x - 32 = x^2
\n" ); document.write( "Combine the x^2's on the left
\n" ); document.write( "x^2 - x^2 + 4x - 32 = 0
\n" ); document.write( "4x = 32
\n" ); document.write( "x = 32/4
\n" ); document.write( "x = 8 units is the side of the square
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\n" ); document.write( "See if this is right
\n" ); document.write( "(8+8) * (8-4) = 8^2
\n" ); document.write( "16 * 4 = 64; confirms our solution of x=8
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