document.write( "Question 549276: A DVD costs 7 times what you get when if you add the number of $ in it's price to the number of cents. This gives it's price in cent . What is it ? Thanks. \n" ); document.write( "
Algebra.Com's Answer #357763 by ankor@dixie-net.com(22740)\"\" \"About 
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A DVD costs 7 times what you get when if you add the number of $ in it's price to the number of cents.
\n" ); document.write( " This gives it's price in cent. What is it?
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\n" ); document.write( "Let d = no. of dollars
\n" ); document.write( "Let c = no. of cents
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\n" ); document.write( "100(d+.01c) = 7(d+c)
\n" ); document.write( "100d + c = 7d + 7c
\n" ); document.write( "100d - 7d = 7c -c
\n" ); document.write( "93d = 6c
\n" ); document.write( "c = \"93%2F6\"d
\n" ); document.write( "reduce the fraction
\n" ); document.write( "c = \"31%2F2\"d
\n" ); document.write( "we can see that an integer solution is possible when d = 2, then c = 31
\n" ); document.write( "Actually we have 3 integer solutions from this equation (c has to be less than 100)
\n" ); document.write( "DVd cost:
\n" ); document.write( " d . c
\n" ); document.write( "$2.31, 7(2+31) = 231 cents
\n" ); document.write( "$4.62, 7(4+62) = 462 cents
\n" ); document.write( "$6.93, 7(6+93) = 693 cents \n" ); document.write( "
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