document.write( "Question 549316: Find all zeros of h(x)= x³ - 9x² + 19x - 35. \n" ); document.write( "
Algebra.Com's Answer #357708 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! Find all zeros of h(x)= x³ - 9x² + 19x - 35 \n" ); document.write( " \r\n" ); document.write( "If there are any rational zeros they have to be ± a divisors of 35.\r\n" ); document.write( "\r\n" ); document.write( "So we try 5\r\n" ); document.write( "\r\n" ); document.write( "5|1 -9 19 -35\r\n" ); document.write( " | 5 -20 -5\r\n" ); document.write( " 1 -4 -1 -40 \r\n" ); document.write( "\r\n" ); document.write( "Nope, 5 is not a zero.\r\n" ); document.write( "\r\n" ); document.write( "So try 7\r\n" ); document.write( "\r\n" ); document.write( "7|1 -9 19 -35\r\n" ); document.write( " | 7 -14 35\r\n" ); document.write( " 1 -2 5 0\r\n" ); document.write( "\r\n" ); document.write( "Yep that's a zero, so we have now factored h(x) as\r\n" ); document.write( "\r\n" ); document.write( "h(x)= x³ - 9x² + 19x - 35\r\n" ); document.write( "h(x)= (x - 7)(x² - 2x + 5)\r\n" ); document.write( "\r\n" ); document.write( "Set each factor = 0\r\n" ); document.write( "\r\n" ); document.write( "x - 7 = 0 x² - 2x + 5 = 0\r\n" ); document.write( " x = 7\r\n" ); document.write( "\r\n" ); document.write( "The first gives back the factor we just found.\r\n" ); document.write( "\r\n" ); document.write( "The second must be solved with the quadratic formula:\r\n" ); document.write( "\r\n" ); document.write( "x = \n" ); document.write( " \n" ); document.write( " |