document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=549366>Question 549366</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 90. The numbers are 6 apart.what are they? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357683 by </B><A HREF=/tutors/aboutme.mpl?userid=TutorDelphia><B>TutorDelphia(193)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TutorDelphia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=TutorDelphia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357683\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There's two ways to do this...one by thinking it out<BR>\n" );
document.write( "If the sum is 90, the average must be 45. If they are 6 digits apart, one must be 3 above 45 and the other 3 below. So our numbers are 42 and 48.\r<BR>\n" );
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document.write( "Solving this algebraically we have<BR>\n" );
document.write( "x+y=90<BR>\n" );
document.write( "x-y=6<BR>\n" );
document.write( "____<BR>\n" );
document.write( "x-y=6<BR>\n" );
document.write( "x=6+y<BR>\n" );
document.write( "substitute this in<BR>\n" );
document.write( "6+y+y=90<BR>\n" );
document.write( "6+2y=90<BR>\n" );
document.write( "2y=84<BR>\n" );
document.write( "y=42\r<BR>\n" );
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document.write( "x+42=90\r<BR>\n" );
document.write( "\n" );
document.write( "x=46 </SPAN>\n" );
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