document.write( "Question 549119: If one side of a square is increased by 4 feet and an adjacent side is decreased by two feet,a rectangle is formed whose area is 12 square feet more than the area of the original square.Find the length of a side of the square. \n" ); document.write( "
Algebra.Com's Answer #357682 by ankor@dixie-net.com(22740)\"\" \"About 
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If one side of a square is increased by 4 feet and an adjacent side is decreased by two feet, a rectangle is formed whose area is 12 square feet more than the area of the original square.Find the length of a side of the square.
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\n" ); document.write( "Let x = the side of the original square
\n" ); document.write( "and
\n" ); document.write( "x^2 = area of the square
\n" ); document.write( "then
\n" ); document.write( "(x+4) = new length of the rectangle
\n" ); document.write( "and
\n" ); document.write( "(x-2) = new width
\n" ); document.write( "then the area of the rectangle
\n" ); document.write( "(x+4)*(x-2) = x^2 - 2x + 4x - 8 = x^2+2x-8
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\n" ); document.write( "\"a rectangle is formed whose area is 12 square feet more than the area of the original square.\"
\n" ); document.write( "x^2 + x - 8 - x^2 = 12
\n" ); document.write( "2x = 12 + 8
\n" ); document.write( "2x = 20
\n" ); document.write( "x = 10 ft is the side of the original square
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\n" ); document.write( "See if this checks out
\n" ); document.write( "(14*8) - (10*10) =
\n" ); document.write( "112 - 100 = 12 \n" ); document.write( "
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