document.write( "Question 53491: I need help with this problem. Can someone write out the steps if possible. Thank you.\r
\n" ); document.write( "\n" ); document.write( "Factor the polynomial into two polynomials of lesser degrees given one of its factors:\r
\n" ); document.write( "\n" ); document.write( "((x^3+2x^2-5x-6; factor: x-2))))))))))
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Algebra.Com's Answer #35768 by tutorcecilia(2152)\"\" \"About 
You can put this solution on YOUR website!
\"%28x%5E3%2B2x%5E2-5x-6%29\"; factor: x-2 [Use synthetic division or regular division to solve]\r
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\n" ); document.write( "Since (x-2) is one of the factors, divide the polynomial by (x-2):
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\n" ); document.write( "x-2=0
\n" ); document.write( "x=2 [Divisor]\r
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\n" ); document.write( "\n" ); document.write( "1+2-5-6 [Use only the coefficients for the dividend]
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\n" ); document.write( "1 [Bring down the very first coefficient of \"1\"]\r
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\n" ); document.write( "\n" ); document.write( "1+2-5-6 [Dividend]
\n" ); document.write( "0+2
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\n" ); document.write( "1+4 [Begin to \"divide\" by 2 by multiplying [(1*2) + 2)=4]\r
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\n" ); document.write( "\n" ); document.write( "1+2-5-6 [Dividend]
\n" ); document.write( "0+2+8
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\n" ); document.write( "1+4+3 [Continue to \"divide\" by 2 by multiplying [(4*2)+(-5)=3]
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\n" ); document.write( "\n" ); document.write( "1+2-5-6 [Dividend]
\n" ); document.write( "0+2+8+6
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\n" ); document.write( "1+4+3+0 [Continue to \"divide\" by 2 by multipling [(3*2) + (-6)=0][Quotient]\r
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\n" ); document.write( "\n" ); document.write( "[Re-apply the coefficents to the \"x\"terms minus one. For example you started with x^3, so the quotient will start with x^2]
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\n" ); document.write( "So, the factors are \"%28x-2%29%28x%5E2%2B4x%2B3%29\"\r
\n" ); document.write( "\n" ); document.write( "Check by multiplying the factors to get the original polynomial.\r
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