document.write( "Question 549353: ln((2x+3)/(x^2-3x+2))^2\r
\n" ); document.write( "\n" ); document.write( "Write expression as the difference of logarithms. Express powers as factors.
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Algebra.Com's Answer #357675 by mathie123(224) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"ln%28%282x%2B3%29%2F%28x%5E2-3x%2B2%29%29%5E2\"$ \r
\n" ); document.write( "\n" ); document.write( "Using the rule $\"%28a%2Fb%29%5Ex=%28a%5Ex%29%2F%28b%5Ex%29\"$ we can write our equation as
\n" ); document.write( " $\"ln%28%28%282x%2B3%29%5E2%29%2F%28%28x%5E2-3x%2B2%29%5E2%29%29\"$ \r
\n" ); document.write( "\n" ); document.write( "Now using the rule $\"ln%28a%2Fb%29=ln%28a%29-ln%28b%29\"$ we can write our equation as
\n" ); document.write( " $\"ln%28%282x%2B3%29%5E2%29-ln%28%28x%5E2-3x%2B2%29%5E2%29\"$ \r
\n" ); document.write( "\n" ); document.write( "And finally using the rule $\"ln%28a%5Ex%29=x%2Aln%28a%29\"$ we can write our equation as
\n" ); document.write( " $\"2%2Aln%282x%2B3%29-2%2Aln%28x%5E2-3x%2B2%29\"$ \r
\n" ); document.write( "\n" ); document.write( "We could also factor out our common factor of 2 if we would like and get:
\n" ); document.write( " $\"2%2A%28ln%282x%2B3%29-ln%28x%5E2-3x%2B2%29%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "Hopefully this helps!:)
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