document.write( "Question 53513: am i posting this is the right place?
\n" ); document.write( "and can you please solve this and show how you did it..thanks\r
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\n" ); document.write( "\n" ); document.write( "A truck can be rented from basic rental for $50 per day plus $0.20 per mile. roadrunners charges $20 per day plus $0.50 per mile to rent the same truck. how many miles must be driven in a day to make the rental cost for basic rental a better deal than that for roadrunners??
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Algebra.Com's Answer #35766 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A truck can be rented from basic rental for $50 per day plus $0.20 per mile. roadrunners charges $20 per day plus $0.50 per mile to rent the same truck. how many miles must be driven in a day to make the rental cost for basic rental a better deal than that for roadrunners??
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\n" ); document.write( "Let \"x\" be the number of miles driven iin a day.
\n" ); document.write( "Basic rental cost = 50+0.20x
\n" ); document.write( "Roadrunner cost = 20+0.50x
\n" ); document.write( "When will Basic be better than Roadrunner?
\n" ); document.write( "When 50+0.20x < 20+0.50x
\n" ); document.write( "30 <0.30x
\n" ); document.write( "x>100 miles
\n" ); document.write( "Basic is cheaper than Roadrunner if the number of miles
\n" ); document.write( "driven in a day is greater than 100.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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