document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=53528>Question 53528</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If Ben invests $4000 at 4% interest per year, how much additional money must he invest at 5 1/2% annual interest to ensure that the interest he recieves each year is 4 1/2% of the total amount invested? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #35765 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=35765\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If Ben invests $4000 at 4% interest per year, how much additional money must he invest at 5 1/2% annual interest to ensure that the interest he recieves each year is 4 1/2% of the total amount invested?<BR>\n" );
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document.write( "Let \"x\" be the amount of additional money.<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "interest + interest = interest<BR>\n" );
document.write( "0.04(4000)+0.055x = 0.045(4000+x)<BR>\n" );
document.write( "160+0.055x=180+0.045x<BR>\n" );
document.write( "0.01x=20<BR>\n" );
document.write( "x=$2000 (amount of additional money he must invest)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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