document.write( "Question 549269: prove that :\r
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document.write( "1. 1+sin A/cos A = sec A + tan A
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document.write( "2. 1-(cos^2 A/1+sinA)= sin A
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document.write( "3. cscA-cotA = sinA/1+cosA
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document.write( "4. sec A - tan A = cos A/1+sinA
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document.write( "5. (1+tanA)/(1-tanA) = (cotA+1/cotA-1) \n" );
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Algebra.Com's Answer #357642 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! prove that :\r \n" ); document.write( "\n" ); document.write( "1. 1+sin A/cos A = sec A + tan A \n" ); document.write( "Change to sines and cosines: \n" ); document.write( "1+sin A/cos A = sec A + tan A \n" ); document.write( "(1 + sin)/cos = 1/cos + sin/cos = (1 + sin)/cos QED \n" ); document.write( "------------------- \n" ); document.write( "2. 1-(cos^2 A/1+sinA)= sin A \n" ); document.write( "Multiply thru by (1 + sin) \n" ); document.write( "1+sin - cos^2 = sin + sin^2 \n" ); document.write( "Add cos^2 \n" ); document.write( "1 + sin = sin + sin^2+ cos^2 \n" ); document.write( "sin^2 + cos^2 = 1 (Pythagorean Identity) \n" ); document.write( "= sin + 1 QED \n" ); document.write( "--------------- \n" ); document.write( "3. cscA-cotA = sinA/1+cosA \n" ); document.write( "change to sines and cosines. email via the TY note for help if needed. \n" ); document.write( "-------------------- \n" ); document.write( "4. sec A - tan A = cos A/1+sinA \n" ); document.write( "change to sines and cosines. email via the TY note for help if needed. \n" ); document.write( "--------------------- \n" ); document.write( "5. (1+tanA)/(1-tanA) = (cotA+1/cotA-1) \n" ); document.write( "change to sines and cosines. email via the TY note for help if needed. \n" ); document.write( "---------- \n" ); document.write( "To do these, you just try things. \n" ); document.write( "Change to sines and cosines and look for something you recognize. \n" ); document.write( " \n" ); document.write( " |